Applying BODMAS rule, #160; 24 ÷ 12+6 of 16 ÷ 32 5 = (24 ÷ 12) + 6 of 16 ÷ 32 5 = 2 + 6 of 16 ÷ 32 5 = 2 + (6 #160; × ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Order of Operations

24÷12+6 of ...

Question

$24 \div 12 + 6$ of $16 \div 32 - 5$

Open in App

Solution

Applying BODMAS rule,
$24 \div 12 + 6$ of $16 \div 32 - 5$
$= (24 \div 12) + 6$ of $16 \div 32 - 5$
$= 2 + 6$ of $16 \div 32 - 5$
$= 2 + (6 \times 16) \div 32 - 5$
$= 2 + 96 \div 32 - 5$
$= 2 + (96 \div 32) - 5$
$= 2 + 3 - 5 = 0$

Suggest Corrections

Similar questions

\frac{(16)^{5}}{(12)^{5}} \times \frac{(24)^{5}}{(32)^{5}}

$\begin{matrix} Class intervals & 0 - 8 & 8 - 16 & 16 - 24 & 24 - 32 & 32 - 40 Frequency & 7 & 12 & 15 & 9 & 6 \end{matrix}$

16

Class	0-4	4-8	8-12	12-16	16-20	20-24	24-28	28-32	32-36
Frequency	6	8	17	23	16	15	-	4	3

(4, 3)

x^{2} + y^{2} = 4

Join BYJU'S Learning Program