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Question

24 g of K2CO3 was treated by a series of reagents to convert all of the carbon to cyanide ions in the complex K3Zn3[Fe(CN)6]2. Calculate the weight of the complex formed.
(Molar mass of K = 39 g/mol, Fe = 56 g/mol, Zn = 65 g/mol)


A
15.85 g
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B
​​​​​10.67 g
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C
6.35 g
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D
20.74 g
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Solution

The correct option is B
​​​​​10.67 g

Let’s assume the weight of the complex compound to be x g.
K2CO3K3Zn3[Fe(CN)6]2

According to the Principle of Atom Conservation (POAC) the number of carbon atoms is conserved.

Applying POAC on C,
1×moles of K2CO3=12×moles of K3Zn3[Fe(CN)6]2

1×weight of K2CO3molar mass of K2CO3=12×weight of the complex compoundmolar mass of the complex compound

1×24138=12×x736

On solving, x=10.67 g
Hence, weight of the complex compound is 10.67 g.

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