24 g of K2CO3 was treated by a series of reagents to convert all of the carbon to cyanide ions in the complex K3Zn3[Fe(CN)6]2. Calculate the weight of the complex formed. (Molar mass of K = 39 g/mol, Fe = 56 g/mol, Zn = 65 g/mol)
A
15.85 g
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B
10.67 g
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C
6.35 g
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D
20.74 g
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Solution
The correct option is B
10.67 g
Let’s assume the weight of the complex compound to be x g. K2CO3⟶K3Zn3[Fe(CN)6]2
According to the Principle of Atom Conservation (POAC) the number of carbon atoms is conserved.
Applying POAC on C, 1×moles ofK2CO3=12×moles ofK3Zn3[Fe(CN)6]2
1×weight ofK2CO3molar mass ofK2CO3=12×weight of the complex compoundmolar mass of the complex compound
1×24138=12×x736
On solving, x=10.67 g Hence, weight of the complex compound is 10.67 g.