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Standard XII

Chemistry

Dehalogenation of Vicinal Dihalide

2,4- hexadiyn...

Question

$2, 4 -$ hexadiyne react with $L i$ in liq. $N H_{3}$ and the formed product is reacted with $C l_{2}$ in $C C l_{4}$ (1 equivalent). Isomers formed as the final product can be:

I I

and

I I I

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I

and

I I I

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I

and

I I

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I

and

V

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Solution

The correct option is C $I$ and $I I I$
2,4-hexadiyne give trans alkene when react with $L i / N H_{3} (l i q)$ . Reaction is known as birch reduction in which further reduction does not takes place.The product on chlorination gives onle I and II isomers as final product by 1,2-addition and 1,4-addition .

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Similar questions

Q. 2,4-hexadiyne

(C_{6} H_{6})

is allowed to react with

L i

N H_{3}

(liq). The product obtained is treated with 1 equivalent of

C l_{2}

C C l_{4}

. Which of the following constitutional isomers are possible products ?

Question 6
What happens when calcium is treated with water?

(i) It does not react with water.
(ii) It reacts violently with water.
(iii) It reacts less violently with water.
(iv) Bubbles of hydrogen gas formed stick to the surface of calcium.

a) (i) and (iv) (b) (ii) and (iii)

Q. Question 8
Two substances, A and B were made to react to form a third substance,

A_{2} B

according to the following reaction

2 A + B \to A_{2} B

. Which of the following statements concerning this reaction are incorrect?
(i) The product

A_{2} B

shows the properties of substances A and B.
(ii) The product will always have a fixed composition.
(iii) The product so formed cannot be classified as a compound.
(iv) The product so formed is an element.

(a) (i), (ii) and (iii)
(b) (ii), (iii) and (iv)
(c) (i), (iii) and (iv)
(d) (ii), (iii) and (iv)

Predict the products formed when cyclohexanecarbaldehyde reacts with following reagents.

(i) PhMgBr and then H₃O⁺

(ii)Tollens’ reagent

(iii) Semicarbazide and weak acid

(iv)Excess ethanol and acid

(v) Zinc amalgam and dilute hydrochloric acid

Column I
( Reagents reacting with

P h C H_{2} C O O H

)

Column II
( Product formed )

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2,4− hexadiyne react with Li in liq.NH3 and the formed product is reacted with Cl2 in CCl4 (1 equivalent). Isomers formed as the final product can be:

The correct option is C I and III2,4-hexadiyne give trans alkene when react with Li/NH3(liq) . Reaction is known as birch reduction in which further reduction does not takes place.The product on chlorination gives onle I and II isomers as final product by 1,2-addition and 1,4-addition .

$2, 4 -$ hexadiyne react with $L i$ in liq. $N H_{3}$ and the formed product is reacted with $C l_{2}$ in $C C l_{4}$ (1 equivalent). Isomers formed as the final product can be: