$24$ iron rods of the same size weigh $240 k g$ . What will be the weight of $20$ such iron rods ?

200

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2000

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120

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100

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Solution

The correct option is A $200$ Kg
Weight of $1$ iron rod $= \frac{240}{24} = 10 k g$
Weight of $20$ iron rods $= 20 \times 10 = 200 k g$

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