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Solving Equations x+a = b and x-a = b by Rearranging Terms

24. ti Solvei...

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24. ti Solveif |z-i|<13,find the maximum value of |z-5-13i|

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Q. Find the missing value:

13 \times (- 24) = . . . . . \times 13

z_{1}, z_{2}, z_{3}, z_{4}, z_{5}

are roots of the equation

z^{5} + z^{4} + z^{3} + z^{2} + z + 1 = 0

, then the value of

∣ ∣ ∣ ∣ 5 \sum i = 1 z_{i}^{4} ∣ ∣ ∣ ∣

Q. Solve the quadratic equation

z^{2} - (8 + 3 i) z + 13 = - 13 i

Q. Two coherent monochromatic light beams of intensities 4I and 9 I are superposed. The maximum and minimum possible intensities in the resulting beam are

Q. In Q. No. 24, (Maximum Value of z + Minimum Value of z) is equal to
(a) 13
(b) 1
(c) –13
(d) –17

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Solving Equations x+a = b and x-a = b by Rearranging Terms

Standard VI Mathematics

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