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Byju's Answer
Standard VI
Mathematics
Divisibility Rule for 9
244 chocolate...
Question
244
chocolates need to be equally distributed among monsters. No chocolates were left undistributed. How many monsters are there?
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Solution
Total number of chocolates
=
244
No chocolates were left undistributed hence, we have to find an option which completely divides
244
.
Option A)
5
We have to find whether or not
244
chocolates can be equally divided among
5
monsters.
The numbers that are divisible by
5
should have
0
or
5
at ones place. Hence,
244
is not divisible by
5
.
Option B)
9
We have to find whether or not
244
chocolates can be equally divided among
9
monsters.
If the sum of the digits of a number is divisible by
9
, then the number itself is divisible by
9
.
Sum of the digits in
244
is
2
+
4
+
4
=
10
.
10
is not divisible by
9
.
Hence,
244
is not divisible by
9
Option C)
4
We have to find whether or not
244
chocolates can be equally divided among
4
monsters.
The number formed by the last two digits of
244
is
44
, which is divisible by
4
. Thus,
244
is divisible by
4
.
Option D)
3
We have to find whether or not
244
can be equally divided among
3
monsters.
A number is completely divisible by
3
if the sum of its digits is divisible by
3
.
The sum of all the digits of
244
is
2
+
4
+
4
=
10
.
10
is not divisible by
3
.
So,
244
is not divisible by
3
Hence, the chocolates were distributed among
4
monsters.
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