Question

2,4,6-Tribromo aniline is a product of:

• A. electrophilic addition on $C_6{H}_5{NH}_2$
• B. electrophilic substitution $C_6{H}_5{NH}_2$
• C. nucleophilic addition on $C_6{H}_5{NH}_2$
• D. nucleophilic substitution on $C_6{H}_5{NH}_2$

Answer 1

The correct option is B electrophilic substitution $C_6{H}_5{NH}_2$

Here, the reaction taking place is bromination (electrophilic aromatic substitution).

Aniline is strongly activated and the $N{H}_2$ group is ortho para directing. Since it is strongly activated, tribromination will occur and all the 2 ortho positions and the para position will be brominated.

So, the product will be 2,4,6-tribromoaniline.