Question

$25.0ml$ of $HCl$ solution gave, on reaction with excess $AgN{O}_3$ solution $2.125g$ of $AgCl$. The molarity of $HCl$ solution is:

• A. $0.25$
• B. $0.6$
• C. $1.0$
• D. $0.75$

Answer 1

The correct option is B $0.6$

Balanced equation is

$HCl+AgN{O}_3\to AgCl+{HNO}_3$

Molecular weight of $AgCl$ = 143

Moles of $AgCl$ present = $\frac{2.125}{143}=0.01486$

According to above reaction, number of moles $AgCl$ = number of moles of $HCl$ = 0.01486.

So, molarity of $HCl$ solution = $\frac{NumberofmolesofHCl}{Volumeofsolutioninlitres}=\frac{0.01486}{\frac{25}{1000}}=0.01486\times 40=0.6M$

So, correct answer is option B.