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Ways of Representing the Concentration of a Solution

25.3 g of sod...

Question

25.3 g of sodium carbonate $N a_{2} C O_{3}$ is dissolved in enough water to make 250 mL of solution .If sodium carbonate dissociates completely molar concentration of sodium ions $N a^{+}$ and carbonate ions are respectively (molar mass of $N a_{2} C O_{3} = 106 g m o l^{- 1}$ )?

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Solution

Number of moles of $N a_{2} C O_{3} = \frac{25.3}{106} = 0.239$ moles
Molarity of solution= $\frac{0.239}{0.25} = 0.956 m o l / l i t r e$
$N a_{2} C O_{3} ⟶ 2 N a^{+} + C O_{3}^{2 -}$
$∴$ Concentration of $C O_{3}^{2 -} = 0.956 M$
Concentration of $N a^{+} = 2 \times 0.956 = 1.912 M$

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25.3

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