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Question

25.3g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250mL of solution. If sodium cabonate dissociates completely, molar concentration of sodium ion, Na+ and carbonate ion CO2−3 are respectively: (Molar mass of Na2CO3=106gmol−1)

A
0.955M and 1.910M
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B
1.910M and 0.955M
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C
1.90M and 1.910M
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D
0.477M and 0.477M
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Solution

The correct option is B 1.910M and 0.955M
Number of moles of Na2CO3=25.3105.96=0.238mol

No. of moles of Na2CO3/volume in liters=0.2380.25 =0.952moleL (1000ml=1L)

Finding the no. of ions:
Na2CO32Na++CO3
(2 moles of Na+ and 1 mole of CO3)
Finding molarity
MolarityofNa+=no. of moles of ions in solution
=2×0.952=1.904moles of Na+/liter
=1.904M
Molarity of CO3=1×0.952
=0.952 moles of carbonate ion/Liter.
So B option is correct.


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