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Ways of Representing the Concentration of a Solution

25.5mL of H...

Question

$25.5$ mL of $H_{2} O_{2}$ solution liberates $0.508$ g of $I_{2}$ from an acidified KI solution. The strength of $H_{2} O_{2}$ solution in terms of volume strength at STP will be.

A

4.48

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B

5.6

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C

9.96

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D

8.20

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Solution

The correct option is A $4.48$
$H_{2} O_{2} + 2 K I \to 2 K O H + I_{2}$
Amount of Iodine libereted = $0.508$
Molar mass of $I_{2} = 127 \times 2 = 254$
Number of mole = $\frac{0.508}{254} = 0.002$ mole
Number of mole of $H_{2} O_{2}$ required = $0.002$
Volume strength of STP = $22.4 \times 0.002$
$= 4.48$

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