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Standard XII

Chemistry

Percentage Composition

25.5g of H2...

Question

25.5g of $H_{2} O_{2}$ solution on decomposition gave 1.68L of $O_{2}$ at STP. The percentage strength by weight of the solution is:

30

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10

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20

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25

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Solution

The correct option is A $20$
Balanced equation for decomposition of $H_{2} O_{2}$

$2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$

2mol $H_{2} O_{2}$ will produce 1 mol $O_{2}$

At STP 1 mol $O_{2}$ has volume = 22.4L

At STP 1.68L of $O_{2}$ = 1.68/22.4 = 0.075 mol $O_{2}$

Therefore the solution contained $0.075 \times 2 = 0.15$ mol $H_{2} O_{2}$

Molar mass $H_{2} O_{2} = 34 g / m o l$

Mass of $H_{2} O_{2}$ decomposed $= 0.15 \times 34 = 5.1$ g $H_{2} O_{2}$ in 25.5g solution

100g solution contains : $100 / 25.5 \times 5.1 = 20$

The original solution contains $20$

Hence, the correct option is $C$

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Similar questions

500ml of $H_{2}$ $O_{2}$ solution liberates 1200ml of $O_{2}$ at STP during its decomposition. The volume strength of $H_{2}$ $O_{2}$ solution is

Q. The srength of

H_{2} O_{2}

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means 1 volume of

H_{2} O_{2}

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The decomposition of

H_{2} O_{2}

is shown as under:

H_{2} O_{2} (a q) \to H_{2} O (l) + \frac{1}{2} O_{2} (g)

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and as reducing agent

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∴, Normality of H_{2} O_{2} Solution = 2 \times Molarity of H_{2} O_{2} Solution

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[Assume that the volume of

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25.5g of H2O2 solution on decomposition gave 1.68L of O2 at STP. The percentage strength by weight of the solution is:

25.5g of $H_{2} O_{2}$ solution on decomposition gave 1.68L of $O_{2}$ at STP. The percentage strength by weight of the solution is: