CameraIcon

SearchIcon

MyQuestionIcon

157

You visited us 157 times! Enjoying our articles? Unlock Full Access!

Calculating Heights and Distances

25. A tower s...

Question

25. A tower stands at the centre of a circular. A and B are the points on the boundary of the park such that AB(=a) subtends an angle of 60 degree at the foot of the tower and the angle of elevation of the top of tower from A orB is 30 degree. Find height of tower

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

Q. A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB (= a) subtends an angle of

60^{\circ}

at the foot of the tower, and the angle of elevation of the top of the tower from A or B is

30^{\circ}

. The height of the tower is

Q. A tower stands vertically on the ground. From a point on the ground, which is

50 m

away from the foot of the tower, the angle of elevation to the top of the tower is

30^{\circ}

. Find the height of the tower.

Q. The angles of elevation of the top of a tower standing on a horizontal plane from two points on a line passing through the foot of the tower at distance

a

b

respectively are complementary angles. Prove that the height of the tower is

\sqrt{a b}

. If the line joining the two points subtends and angle

θ

at the top of the tower, show that

sin θ = \frac{(a - b)}{(a + b)}

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Questions

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Calculating Heights and Distances

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon