Question

$25g$ of $M{Cl}_4$ contains $0.5$ mole chlorine then its molecular weight is:

• A. $100g{mol}^{-1}$
• B. $200g{mol}^{-1}$
• C. $150g{mol}^{-1}$
• D. $400g{mol}^{-1}$

Answer 1

Answer: (B)

$200g{mol}^{-1}$

From the given weight of $MC{l}_4$

$\frac{25g}{0.5mol}⟹\frac{50g}{1mol}$

As there are $4$ moles of chlorine’s in 1 mole of $MC{l}_4$ then molecular weight of $MC{l}_4$ can be calculated as,
$\therefore \frac{50g}{1mol}\times 4mol$ $=200g$

Hence $200gmo{l}^{-1}$ is the answer.

Option $B$ is correct.