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Arrhenius Acid

25 mL of 0....

Question

$25$ mL of $0.50$ M $H_{2} O_{2}$ solution is added to $50$ mL of $0.20$ M $K M n O_{4}$ in acid solution. Which of the following statement(s) is/are true?

A

0.010

mol of oxygen is liberated.

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B

0.005

mol of

K M n O_{4}

does not react with

H_{2} O_{2}

.

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C

0.0125

gram-mole of oxygen gas is evolved.

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D

0.0025

mol

H_{2} O_{2}

does not react with

K M n O_{4}

.

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Solution

The correct options are
B $0.005$ mol of $K M n O_{4}$ does not react with $H_{2} O_{2}$ .
D $0.0125$ gram-mole of oxygen gas is evolved.
The balanced reaction is as follows:
$2 M n O_{4}^{-} + 5 H_{2} O_{2} + 6 H^{+} ⟶ 2 M n^{2 +} + 5 O_{2} + 8 H_{2} O$
2 5 6
Initial moles 0.01 0.0125
After completion 0.005 - 0.0125

Here, $H_{2} O_{2}$ is the limiting agent and it is consumed completely.
So, $0.005$ mol of $K M n O_{4}$ does not react with $H_{2} O_{2}$ and is left unreacted.
$O_{2}$ evolved $= 0.0125 \times 32 = 0.4$ g.

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