25 ml of a solution containing HCl and sulphuric acid required 10 ml of a 2.0 N NaOH solution for neutralisation. 10 ml of the same acid mixture on being treated with an excess of BaCl2 gave 0.699 gm of BaSO4. The normality of HCl is .
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Solution
X1 mmol of HCl and X2 mmol of H2SO4 are present in 25 ml acid mixture. So, X1+2X2=10×2 (1) Again, BaCl2+H2SO4→BaSO4+2HCl Since we are taking only 10 ml of the acidic solution, X2×1025=0.699233 ⇒X2=7.5mmol ⇒X1=5mmol So, normality of HCl=525=0.2N