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Ways to Define Concentration

25 mL of a so...

Question

$25$ mL of a solution of $F e^{2 +}$ ions was titrated with a solution of the oxidising agent $C r_{2} O_{7}^{2 -} . 32.45$ mL of $0.0153$ M $K_{2} C r_{2} O_{7}$ solutin was required. What is the molarity of the $F e^{2 +}$ solution?

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Solution

${F e}^{2 +} + {C r}_{2} O_{7}^{2 -} \to {C r}^{3 +} + {F e}^{3 +}$
$25 m l$ $32.45 m l$
$M =$ ? $0.0153 M$

$n_{f}$ for ${C r}_{2} O_{7}^{2 -} = 6$

Now,
meq of ${F e}^{2 +} =$ meq. of ${C r}_{2} O_{7}^{2 -}$

$25 \times M \times 1 = 32.45 \times 0.0153 \times 6$

$M = \frac{32.45 \times 0.0153 \times 6}{25} = 0.1192 M$

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25

mL of a solution of

F e^{2 +}

ions was titrated with a solution of the oxidising agent

C r_{2} O_{7}^{2 -}

32.45

0.0153

K_{2} C r_{2} O_{7}

solution was required. What is the molarity of the

F e^{2 +}

10 m L

of an aqueous solution of

F e^{2 +}

ions was titrated in the presence of dil

H_{2} S O_{4}

using diphenylamine indicator,

15 m L of

0.02 M

K_{2} C r_{2} O_{7}

was required to get the end point. The molarity of the solution containing

F e^{2 +}

x \times 10^{- 2} M

x

is ___. (Nearest integer)

Q. A mixture of

F e O

F e_{2} O_{3}

is completely reacted with

100 mL

0.25 M

K M n O 4

solution. The resultant solution was then titrated with

Z n

dust which converted the

F e^{3 +}

F e^{2 +}

F e^{2 +}

1000 mL

0.10 M

K_{2} C r_{2} O_{7}

solution. Find out the weight percentage of

F e_{2} O_{3}

in the mixture.

Q. The following titration method is given to determine the total content of the species with variable oxidation states. Answer the question given at the end of it.

25.0

mL of solution containing both

F e^{2 +}

F e^{3 +}

ions is titrated with

25.0

0.02 M

K M n O_{4}

H_{2} S O_{4}

). As a result, all of the

F e^{2 +}

ions are oxidised to

F e^{3 +}

25

mL of the original solution is treated with

Z n

metal. Finally, the solution requires

40.0

K M n O_{4}

solution for oxidation to

F e^{3 +}

.

{M n O_{4}}^{-} + 5 F e^{2 +} + 8 H^{+} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O

The molar concentration of

F e^{2 +}

in the original solution is :

10 g

C u S

C u_{2} S

was treated with

100 m L

1.25 M K_{2} C r_{2} O_{7}

C r^{3 +}, C u^{2 +}

S O_{2}

. The excess oxidant was reacted with

50 m L

F e^{2 +}

25 m L

F e^{2 +}

solution required

0.875 M K M n O_{4}

under acidic condition, the volume of

K M n O_{4}

20 m L

. Find the percentage of

C u_{2} S

in the sample.
Given: molar mass of

C u

63.5 g m o l^{- 1}

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