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Characteristics of Chemical Reaction

25 mL of N/...

Question

$25 m L$ of $N / 10$ caustic soda solution exactly neutralises $20 m L$ of an acid solution containing $7.875 g$ of acid per litre. Calculate the equivalent mass of the acid.

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Solution

$N_{1} V_{1} (N a O H) = N_{2} V_{2} (A c i d)$
$\frac{1}{10} \times 25 = N_{2} \times 20$
$N_{2} = \frac{25}{10 \times 20} = 0.125$
$S t r e n g t h = N o r m a l i t y \times E q . m a s s$
Eq. mass of the acid $= \frac{7.875}{0.125} = 63.00$ .

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