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Byju's Answer
Standard XII
Physics
Newton's Second Law: Rotatory Version
25.Two rotati...
Question
25.Two rotating bodies A and B of masses m and 2m with moments of inertia IA and IB (IB > IA) have equal kinetic energy of rotation . If LA and LB be their angular momenta respectively then 1- LA = LB/2 2- LA= 2LB 3- LB > LA 4- LA > LB
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Similar questions
Q.
Two rotating bodies
A
and
B
of masses
m
and
2
m
with moments of inertia
I
A
and
I
B
(
I
B
>
I
A
)
have equal kinetic energy of rotation. If
L
A
and
L
B
be their angular momenta respectively, then
Q.
Two rotating bodies
A
and
B
of masses m and 2m with moments of inertia
I
A
and
I
B
(
I
B
>
I
A
)
have equal kinetic energy of rotation. If
L
A
and
L
B
be their angular moment a respectively, then:
Q.
Two bodies,
A
and
B
with moment of inertia
I
A
and
I
B
(
I
B
>
I
A
)
have equal rotational kinetic energy are rotating about the same axis. If
L
A
and
L
B
be their angular momentum respectively then
Q.
Two rigid bodies
A
and
B
rotate with angular momenta
L
A
and
L
B
respectively. The moments of inertia of
A
and
B
about the axes of rotation are
I
A
and
I
B
respectively. If
I
A
=
I
B
/
4
and
L
A
=
5
L
B
. Then the ratio of rotational kinetic energy
K
A
of
A
to the rotational energy
K
B
of
B
is given by
Q.
Two rigid bodies A and B rotate with rotational kinetic energies
E
A
and
E
B
respectively. The moments of inertia of A and B about the axis of rotation are
I
A
and
I
B
respectively.
If
I
A
=
I
B
/
4
and
E
A
/
100
=
E
B
the ratio of angular momentum
(
L
A
)
of A to the angular momentum
(
L
B
)
of B is
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Newton's Second Law: Rotatory Version
Standard XII Physics
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