250 mL of a sodium carbonate solution contains 2.65 g of Na2CO3. If 10 mL of this solution is diluted to 1 L, what is the concentration of the resultant solution? (Molar mass of Na2CO3 = 106 g/mol)
A
0.001 M
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B
0.01 M
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C
0.1 M
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D
10−4 M
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Solution
The correct option is A 0.001 M Number of moles =given massmolar mass=2.65106=0.025mol
Molarity=number of moles of solutevolume of solution in mL×1000
Molarity=0.025250×1000=0.1M Conserving moles before and after dilution: M1V1=M2V2 Where M2 and V2 are the final concentration and volume, respectively. So, (0.1×10)=M2×1000 M2=0.001M Therefore, the final concentration of the solution is 0.001M.