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Molarity

250 ml of sod...

Question

250 ml of sodium carbonate solution contains 2.65g of ${N a}_{2} {C O}_{3}$ . If 10 ml of the solution is diluted to 1 L. What is the concentration of the resultant solution?

0.1 M

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0.001 M

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0.01 M

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10^{4} M

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Solution

The correct option is B $0.001 M$
Molarity of $N a_{2} C O_{3},$

$M_{1} = \frac{2.65}{106} \times \frac{1000}{250}$

$= 0.1 M$

$M_{1} = 0.1 M$
$V_{1} = 10 m l$
$V_{2} = 1000 m l$

So $M_{1} V_{1} = M_{2} V_{2}$

$0.1 \times 10 = M_{2} \times 1000$

$M_{2} = 0.001 M$

The correct option is 'B'

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