$250 m l$ round bottom flask containing air was heated from $27^{o} C$ to $477^{o} C$ . Calculate what fraction of the air is left behind in the flask.

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Solution

Since pressure is constant in atmosphere so
$\frac{V}{T} =$ constant
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
$V_{1} = 250 m l T_{1} = 27^{o} C + 273 = 300 K$
$V_{2}$ ? $T_{2} = 477^{o} + 273 = 750 K$
$\frac{250 m l}{300 K} = \frac{V_{2}}{750 K}$
$V_{2} = \frac{250}{300} \times 750 = 625 m l$
fraction of a left behind $= \frac{250}{625} = 2 / 5$

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250ml round bottom flask containing air was heated from 27oC to 477oC. Calculate what fraction of the air is left behind in the flask.

Since pressure is constant in atmosphere soVT= constantV1T1=V2T2V1=250 mlT1=27oC+273=300 KV2? T2=477o+273=750 K250 ml300 K=V2750 KV2=250300×750=625 mlfraction of a left behind =250625=2/5

$250 m l$ round bottom flask containing air was heated from $27^{o} C$ to $477^{o} C$ . Calculate what fraction of the air is left behind in the flask.