2500 kg m−3 = ___ g cm−3
0.25
2.5
25
250
2500 kg m−3= 2500×1000 g×(100 cm)−3
= 2500×1000×1100×1100×1100g cm−3
=2.5 g cm−3
The coagulation of 100 ml of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance “X” to it before adding 1 ml of 10% NaCl solution. The gold number of “X” is
On the addition of 1 ml. of 10% solution of sodium chloride to 10 ml. of gold sol in presence of 0.025 g of starch, the coagulation is just prevented. The gold number of starch is