Question

$252$ gm of oxalic acid with molecular formula $C_2{H}_2{O}_4\cdot 2H_{2}O$ dissolve in water to form $250$ ml. of the solution. Its molarity will be:

• A. 16 M
• B. 8 M
• C. 32 M
• D. 24 M

Answer 1

The correct option is B 8 M

Molar mass of oxalic acid $=126.1g$

Number of moles of solute $=\frac{250}{126.1}=2mole$

Molarity (M) $=\frac{numberofmolesofsolute}{volumeofsolutioninliters}$

$=\frac{2}{0.25}=8M$