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Stoichiometric Calculations

254 g of iodi...

Question

254 g of iodine and 142g of chlorine are made to react completely to give a mixture of $I C l$ and $I C l_{3}$ . The moles of each one formed is:

0.1

I C l

and 0.1 mol

I C l_{3}

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1.0 mol

I C l

and 1.0 mol

I C l_{3}

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0.5

I C l

and 0.1 mol

I C l_{3}

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0.5 mol

I C l

and 1.0 mol

I C l_{3}

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Solution

The correct option is A 0.1 $I C l$ and 0.1 mol $I C l_{3}$
$I_{2} + C l_{2} ⟶ 2 I C l$ ;
$I_{2} + 3 C l_{2} ⟶ 2 I C l_{3}$
No. of moles of iodine $= \frac{254}{254} = 1$
No. of moles of chlorine $= \frac{142}{71} = 2$
$1$ $m o l e$ of $I_{2}$ react with $2$ $m o l e$ of chlorine
$⟹ I_{2} + 2 C l_{2} ⟶ I C l + I C l_{3}$
It gives $1$ $m o l e$ of $I C l$ and $1$ $m o l e$ of $I C l_{3}$

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Similar questions

25.4 g of iodine and 7.1 g chlorine are made to react to give a mixture of ICl and $I C l_{3}$ . Number of moles of ICl and $I C l_{3}$ formed are respectively ?

25.4

g of iodine and

14.2

g of chlorine are made to react completely to yield a mixture of

I C l

and

I C l_{3}

. Calculate the number of moles of

I C l

and

I C l_{3}

formed.

25.4

g of iodine and

14.2

g of chlorine are made to react completely to yield a mixture of

I C l

and

{I C l}_{3}

. Calculate the ratio of moles of

I C l

and

{I C l}_{3}

25.4 g

I_{2}

and

14.2 g

C l_{2}

are made to react completely to yield a mixture of

I C l

and

I C l_{3}

. Calculate the number of moles of

I C l

and

I C l_{3}

. (Given: Molar mass of

I

127

g / m o l

)

25.4

g of

I_{2}

and

14.2

g of

C l_{2}

are made to react completely to yield a mixture of

I C l

and

I C l_{3}

.
Calculate moles of

I C l

and

I C l_{3}

formed.

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254 g of iodine and 142g of chlorine are made to react completely to give a mixture of ICl and ICl3. The moles of each one formed is:

The correct option is A 0.1 ICl and 0.1 mol ICl3I2+Cl2⟶2ICl;I2+3Cl2⟶2ICl3No. of moles of iodine =254254=1No. of moles of chlorine =14271=21 mole of I2 react with 2 mole of chlorine⟹I2+2Cl2⟶ICl+ICl3It gives 1 mole of ICl and 1 mole of ICl3

254 g of iodine and 142g of chlorine are made to react completely to give a mixture of $I C l$ and $I C l_{3}$ . The moles of each one formed is: