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Question

25a24 can be factorized as:


A

(5a + 2) (5a + 2)

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B

(5a - 2) (5a - 2)

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C

(5a + 2) (5a - 2)

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D

(5a + 12) (5a - 12)

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Solution

The correct option is C

(5a + 2) (5a - 2)


25a24 is in the form of a2b2
So, the identity a2b2 =(ab)(a+b) can be used.

25a24 = (5a)222 = (5a+2)(5a2)


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