The correct option is A 5b^225a^2 b^3 nbsp; ÷ 5a^2b =25a^2 b^3/5a^2b = 25 × nbsp; a × a × b × b × b/5 × a × a × b (rewriting in irreducible factor forms) ...

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Standard VIII

Mathematics

Division of a Monomial by Another Monomial

25 a2 b3÷ 5 a...

Question

$25 a^{2} b^{3} \div 5 a^{2} b =$ ___________.

5 b^{2}

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5 a^{2}

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5 a^{2} b^{2}

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5 a b^{2}

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Solution

The correct option is A $5 b^{2}$
$25 a^{2} b^{3} \div 5 a^{2} b$

$= \frac{25 a^{2} b^{3}}{5 a^{2} b}$

$= \frac{25 \times a \times a \times b \times b \times b}{5 \times a \times a \times b}$
(rewriting in irreducible factor forms)

$= 5 \times b \times b$

$= 5 b^{2}$

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Similar questions

When we add $5 a^{2} b + 6 a b + 7 b c + 54$ to $14 a b + 8 b c + 16$ , we will get:

The coefficient of $b$ in $- \frac{5 a^{2} b}{8 c}$ is:

Q. Subtract

3 a^{2} b

from

- 5 a^{2} b

Q. Subtract:
3a²b from −5a²b

The coefficient of $b$ in - $\frac{5 a^{2} b}{8 c}$ is:

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25a2b3÷5a2b= ___________.

The correct option is A 5b225a2b3÷5a2b =25a2b35a2b =25×a×a×b×b×b5×a×a×b (rewriting in irreducible factor forms) =5×b×b =5b2

$25 a^{2} b^{3} \div 5 a^{2} b =$ ___________.

The correct option is A $5 b^{2}$
$25 a^{2} b^{3} \div 5 a^{2} b$

$= \frac{25 a^{2} b^{3}}{5 a^{2} b}$

$= \frac{25 \times a \times a \times b \times b \times b}{5 \times a \times a \times b}$
(rewriting in irreducible factor forms)

$= 5 \times b \times b$

$= 5 b^{2}$