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Atomic Number and Mass Number

26.8 gm of ...

Question

26.8 gm of $N a_{2} S O_{4} . n H_{2} O$ contains 12.6 gm of water. The value of 'n' is:

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Solution

The correct option is D 7
$N a S O_{4} \cdot n H_{2} O$
Molar mass $= (142 + 18 n)$
Here number of moles of water $= \frac{12.6}{26.8}$
Mass of water $= \frac{12.6}{26.8} \times (142 + 18 n)$
$18 n = \frac{12.6}{26.8} \times (142 + 18 n)$
$n = 7$

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