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Reactions of Sulphuric Acid

26. Heat of d...

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26. Heat of dissociation of acetic acid is 0.005 kcal per g hence enthalpy change when 1 mol of calcium hydroxide is completely neutrilised is?

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1 g

equivalent of strong acid reacts with strong base heat released is

13.5 K c a l

1 g

H_{2} A

is completely neutralised against strong base

13 K c a l

is released. When

1 g

B (O H)_{2}

is completely neutralised against strong acid 10 Kcal heat is released. Calculate enthalpy change when 1 mole

H_{2} A

is completely neutralized by

B (O H)_{2}

.

Q. The heat of neutralisation of oxalic acid is

- 25.4 K c a l m o l^{- 1}

using strong base,

N a O H

. Hence, the enthalpy change of the process is

H_{2} C_{2} O_{4} \to\leftarrow 2 H^{\oplus} + C_{2} O_{4}^{2 -}

H_{2} S O_{4}

is completely neutralised by sodium hydroxide, the heat liberated is 114.64 KJ. what is the enthalpy of neutralisation ?

Q. Enthalpy of neutralisation of acetic acid by

N a O H

- 50.6 k J m o l^{- 1}

Δ H

for ionisation of

C H_{3} C O O H

. Given, the heat of neutralisation of a strong acid with a strong base is

- 55.9 k J m o l^{- 1}

.

Q. The heat of neutralization is the change in enthalpy that occurs when one equivalent of an acid and one equivalent of a base undergo a neutralization reaction to form water and a salt. Heat of neutralization of strong acid with strong base is

- 13.7 k c a l m o l^{- 1}

\begin{matrix} List - I & List - II (|Enthalpy change in kcal|) & (Neutralisation) (I) < 13.7 kcal & (P) H C l 1 mol + N a O H 1 mol (II) = 13.7 kcal & (Q) H F 1 mol + N a O H 1 mol (III) > 13.7 kcal & (R) H C l 1 mol + N H_{4} O H 1 mol (IV) = 27.4 kcal & (S) N a O H 2 mol + H_{2} S O_{4} 1 mol (T) N a O H 1 mol + C H_{3} C O O H 1 mol \end{matrix}

Which of the following options has the correct combination considering List-I and List-II?

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