Dear Student,
The configuration of electrons of the atoms are as below,
Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2 { for Z=26}
Fe2+ = 1s2 2s2 2p6 3s2 3p6 3d6
so we get retained d = 6-orbital
p-electron in Cl (Z=17) is 11(2p63p5)
d-electron in Fe (Z=26) is 6(d6)
p-electron in Ne (Z=10) is 6(2p6)
s-electron in Mg (Z=12) is 6(1s22s23s2)
from the above analysis answer is Option (A) p-electron in Cl which does not equal with d-electron of Fe2+
Regards.