(i) Plotting the points A (4, 6) and B (1, 2) on the given graph.
(ii) The co-ordinates of the image of A when reflected in axis are A’(4, -6)
(iii) The co-ordinates of the image of B when reflected in the line AA’ are B’ = (7, 2)
(iv) It’s seen that in the quadrilateral ABA’B’, we have
AB = AB’ and A’B = A’B’
Thus, ABA’B’ is a kite.