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Question
27 - 125a³-135a + 225a² factorize
27 - 125a³-135a + 225a² factorize
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Solution
27 – 125a³ – 135a + 225a²
By identity [(a + b)³ = a³ + b³ + 3a²b + 3ab²]
= (3)³ + (-5a)³ + 3 x (3)² x (-5a) + 3 x 3 x (-5a)²
= (3 - 5a)³
By identity [(a + b)³ = a³ + b³ + 3a²b + 3ab²]
= (3)³ + (-5a)³ + 3 x (3)² x (-5a) + 3 x 3 x (-5a)²
= (3 - 5a)³
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