Question

${}_{13}^{27}Al$ is a stable. ${}_{13}^{29}Al$ is expected to disintegrate by:

• A. $\alpha$-emission
• B. $\beta$-emision
• C. positron emission
• D. neutron emission

Answer 1

The correct option is D neutron emission

For ${}_{13}^{29}Al$, n/p ratio is high so they stablizes through beta emission or neutron emission.