27.6 g of K2CO3 was treated by a series of reagents so as to convert all of its carbon to K2Zn3[Fe(CN)6]2. Calculate the mass of the product formed. (round it to nearest integer value)
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Solution
Following conservation of atoms of carbon, 27.6gK2CO3=27.6×12138=2.4g carbon. So, mass of product forms K2Zn3[Fe(CN)6]2=698×2.4144=11.63g. So, integer value is 12.