27 - 3 - 4 - 7 - 18 - -1

The correct option is D × and + The given equation is : nbsp;27 nbsp; ÷ 3 (4 + 7) × 18 = 1(A) After interchanging ÷ and × T ...

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Byju's Answer

Standard VII

Mathematics

Integers

27 ÷ 3 - 4 ...

Question

27 $\div$ 3 - (4 + 7) $\times$ 18 = -1

\div a n d \times

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+ a n d -

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- a n d \div

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\times a n d +

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Solution

The correct option is D $\times a n d +$
The given equation is : 27 $\div$ 3 - (4 + 7) $\times$ 18 = -1
(A) After interchanging $\div$ and $\times$
The equation is $27 \times 3 - (4 + 7) \div 18 = 81 - 11 \div 18 = 70 \div 18 = 35 \div 9 \neq - 1$
(B) After interchanging + and -
The equation is $27 \div 3 + (4 - 7) \times 18 = 9 - 3 \times 18 = 6 \times 18 = 54$
(C) After interchanging $-$ and $\div$
The equation is $27 - 3 \div (4 + 7) \times 18 = 24 - 3 \div 11 \times 18 = 21 \div 11 \times 18 = 34.33$
(D) After interchanging $\times$ and $+$
The equation is $27 \div 3 - (4 \times 7) + 18 = 9 - 28 + 18 = 27 - 28 = - 1$
Thus, option (D) is correct.

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-7/27 and 11/18

Add the following rational numbers:
(i) $\frac{3}{4}$ and $\frac{- 3}{5}$
(ii) $\frac{5}{8}$ and $\frac{- 7}{12}$
(iii) $\frac{- 8}{9}$ and $\frac{11}{6}$
(iv) $\frac{- 5}{16}$ and $\frac{7}{24}$
(v) $\frac{7}{- 18}$ and $\frac{8}{27}$
(vi) $\frac{1}{- 12}$ and $\frac{2}{- 15}$
(vii) $- 1$ and $\frac{3}{4}$
(viii) $2$ and $\frac{- 5}{4}$
(ix) $0$ and $\frac{- 2}{5}$