27 g Al will react completely with:

4 g o f O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 g o f O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27 g o f O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24 g o f O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $24 g o f O_{2}$
The balance equation is

$4 A l + 3 O_{2} \to 2 A l_{2} O_{3}$

Atomic mass of $A l = 27$ g

Atomic mass of $O_{2} = 2 \times 16 = 32$ g

Mole ratio , $A l : O_{2} = 4 : 3$

$= 1 : \frac{3}{4}$

Mass of $O_{2}$ required $= \frac{3}{4} \times 32 = 24$ g

$24$ g of oxygen is required.

Suggest Corrections

Similar questions

A l

_{2}

_{3}

27g Al reacts completely with how many grams Oxygen.

27

A l

A l

Join BYJU'S Learning Program