27. Prove that,tan35+tan10+tan35tan10=1

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tan 20^{\circ} tan 35^{\circ} tan 45^{\circ} tan 55^{\circ} tan 70^{\circ} = 1

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\frac{secθ + tanθ - 1}{tanθ - secθ + 1} = \frac{cosθ}{1 - sinθ}

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sin (50^{\circ} + θ) - cos (40^{\circ} - θ) + tan 1^{\circ} tan 10^{\circ} tan 20^{\circ} tan 70^{\circ} tan 80^{\circ} tan 89^{\circ} = 1

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