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Question

27 spherical iron balls of radius 5 cm each are melted and recasted into a big sphere.The radius of the big sphere is .

A
3 cm
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B
9 cm
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C
15 cm
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D
5 cm
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Solution

The correct option is C 15 cm

Volume of the big iron ball will be equal to the volume of 27 small iron balls.
Let the radius of the big sphere be R cm.
Let the radius of the small sphere be
r cm = 5 cm.

43×πR3=27×(43×πr3)

R3=27r3

R=3r=3×5=15 cm.


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