27 spherical iron balls of radius 5 cm each are melted and recasted into a big sphere.The radius of the big sphere is
Volume of the big iron ball will be equal to the volume of 27 small iron balls.
Let the radius of the big sphere be R cm.
Let the radius of the small sphere be
r cm = 5 cm.
⇒ 43×πR3=27×(43×πr3)
⇒R3=27r3
R=3r=3×5=15 cm.