Question

$272$calories of heat energy is required to heat$0.02kg$ of a metal of specific heat capacity$170calk{g}^{-1}°C^{-1}$to a temperature T. If the initial temperature of the metal is$20°C$, calculate the final temperature T.

Answer 1

Step 1: Given data

mass$\left(m\right)=0.02kg$

Heat supplied$=272calories$

Specific heat capacity$\left(c\right)=170calk{g}^{-1}°C^{-1}$

Initial temperature$=20°C$

Final temperature (T)=?

Rise in temperature$={\theta }_R$

Step 2: calculating the final temperature

Heat supplied to metal$=mc{\theta }_R$

$$\begin{gathered} \Rightarrow 272calories=0.02kg\times 170calk{g}^{-1}°C^{-1}\times {\theta }_R \\ \Rightarrow {\theta }_R=\frac{272}{0.02\times 170}=\frac{272}{3.4} \\ \Rightarrow {\theta }_R=80°C \end{gathered}$$

Final temperature= rise in temperature$+$initial temperature

$=(80+20)°C=100°C$

The final temperature of the metal is$100°C$.