$27 x^{2} - 10 x + 1 = 0$

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Solution

Here $27 x^{2} - 10 x + 1 = 0$

Comparing the given quadratic equation with $a x^{2} + b x + c = 0$ , we have

a=27, b=-10 and c=1

$∴ x = \frac{- (- 10) \pm \sqrt{(- 10)^{2} - 4 \times 27 \times 1}}{2 \times 27}$

$= \frac{10 \pm \sqrt{100 - 108}}{54} = \frac{10 \pm 2 \sqrt{2} i}{54}$

$= \frac{5 \pm \sqrt{2} i}{27}$

Thus $= \frac{5 + \sqrt{2} i}{27} a n d x = \frac{5 - \sqrt{2} i}{27}$

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