Question

28. Complete and balance the following equation:-

• $\mathrm{NaCl}+{\mathrm{H}}_2{\mathrm{SO}}_4\to$

Answer 1

Step 1: Write the skeletal equation for the given reaction

Sodium chloride (NaCl) reacts with Sulphuric acid (H₂SO₄) and forms Sodium bisulfate (NaHSO₄). The skeletal chemical equation is as follows:

$\underset{\mathrm{Sodium}\mathrm{chloride}}{\mathrm{NaCl}\left(\mathrm{s}\right)}+\underset{\mathrm{Sulphuric}\mathrm{acid}}{{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{l}\right)}\to \underset{\mathrm{Sodium}\mathrm{sulphate}}{{\mathrm{NaHSO}}_4\left(\mathrm{s}\right)}+\hspace{0.17em}\underset{\mathrm{Hydrochloric}\mathrm{acid}}{\mathrm{HCl}\left(\mathrm{g}\right)}$

Step 2: Count the number of atoms of each element on both sides of the equation

For balancing the equation, both reactants and products should be balanced on both sides. The number of atoms of each element present on both sides of the equation is listed below in the table:

Reactant	Product
Na - 1	Na - 1
Cl - 1	Cl - 1
H - 2	H - 2
S - 1	S - 1
O - 4	O - 4

Since the number of atoms is equal on both sides thus, the equation is said to be balanced.

Therefore, the balanced chemical equation for the given reaction is as follows:

$\underset{\mathrm{Sodium}\mathrm{chloride}}{\mathrm{NaCl}\left(\mathrm{s}\right)}+\underset{\mathrm{Sulfuric}\mathrm{acid}}{{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{l}\right)}\to \underset{\mathrm{Sodium}\mathrm{sulfate}}{{\mathrm{NaHSO}}_4\left(\mathrm{s}\right)}+\hspace{0.17em}\underset{\mathrm{Hydrochloric}\mathrm{acid}}{\mathrm{HCl}\left(\mathrm{g}\right)}$