Question

$28$ g of a metal requires $24.5$ g of sulphuric acid to get dissolved. Calculate the equivalent weight of metal and the volume of hydrogen liberated at STP.

Answer 1

Molecular weight of Sulphuric acid = 98

Equivalent weight = 98/2 = 49

Let E be the equivalent weight of metal

According to law of chemical equivalence,

Number of gram equivalent of metal = Number of gram equivalents of sulphuric acid

28/E = 24.5/49

E = 56

Now one equivalent of a metal liberate one equivalent volume of hydrogen

Hydrogen is a diatomic gas with valency 1

Equivalent volume of hydrogen = 11.2L at STP It means 56 g of metal liberate 11.2 L hydrogen

Hence, Volume of hydrogen liberated by 28g metal = (11.2 x 28)/ 56 = 5.6 L