You visited us 35 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Ideal Gas Equation

28 gm of N2...

Question

$28 g m$ of $N_{2}$ gas is contained in a flask at a pressure of $10 a t m$ and at a temperature of $57^{\circ}$ . It is found that due to leakage in the flask, the pressure is reduced to half and the temperature reduced to $27^{\circ} C$ . The quantity of $N_{2}$ gas that leaked out is:

11 / 20 g m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20 / 11 g m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 / 63 g m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

63 / 5 g m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $11 / 20 g m$
The ideal gas law must hold before & after the leakage of gas.
Thus, $\frac{P_{i} V}{n_{i} T_{i}} = \frac{P_{f} V}{n_{f} T_{f}}$
$\Rightarrow n_{f} = \frac{P_{f}}{P_{i}} \frac{T_{i}}{T_{f}} n_{i}$
$\Rightarrow n_{f} = \frac{1}{2} \frac{273 + 57}{273 + 27} n_{i}$
$= \frac{11}{20} n_{i}$
$\Rightarrow m_{f} = \frac{11}{20} m_{i}$
Thus, leaked out mass $= \frac{9}{20} m_{i} = \frac{63}{5} g$

Suggest Corrections

Similar questions

28 g m

N_{2}

gas is contained in a flask at a pressure of

10 a t m

and at a temperature of

57^{o}

. It is found that due to leakage in the flask, the pressure is reduced to half and the temperature reduced to

27^{o} C

. The quantity of

N_{2}

gas that leaked out is_________.

Q. 28 G of N2 gas is contained in a flask at a pressure of 10 atm and at a temperature of

57^{\circ} C

. It is found that due to leakage in the flask, the pressure is reduced to half and the temperature to

27^{\circ} C

. The quantity of

N_{2}

gas that leaked out is

28

g

N_{2}

gas is contained in a flask at a pressure

10

a t m

and at a temperature of

57^{0}

C

. It is found that due to leakage in the flask, the pressure is reduced to half and the temperature reduced to

27^{0}

C

.The quantity of

N_{2}

gas that leaked out is:

Q. A flask of

4.48

L capacity contains a mixture of

N_{2}

and

H_{2}

0^{o}

C and

1

atm pressure. If the mixture is made to react to form

N H_{3}

gas at the same temperature, the pressure in the flask reduces to

0.75

atm. The partial pressure of

N H_{3}

gas in the final mixture is?

Q. A

5 l i t

flask containing

N_{2}

1

bar and

25^{o} C

is connected to a

4 l i t

flask containing

N_{2}

2

bar and

0^{o} C

. After the gases are allowed to mix keeping both flasks at their original temperature, what will be the pressure and amount of

N_{2}

in the

5 l i t

flask assuming ideal gas behaviour.

Join BYJU'S Learning Program

28 gm of N2 gas is contained in a flask at a pressure of 10 atm and at a temperature of 57∘. It is found that due to leakage in the flask, the pressure is reduced to half and the temperature reduced to 27∘C. The quantity of N2 gas that leaked out is:

The correct option is C 11/20 gmThe ideal gas law must hold before & after the leakage of gas.Thus, PiVniTi=PfVnfTf⇒nf=PfPiTiTfni⇒nf=12273+57273+27ni=1120ni⇒mf=1120miThus, leaked out mass=920mi=635g

$28 g m$ of $N_{2}$ gas is contained in a flask at a pressure of $10 a t m$ and at a temperature of $57^{\circ}$ . It is found that due to leakage in the flask, the pressure is reduced to half and the temperature reduced to $27^{\circ} C$ . The quantity of $N_{2}$ gas that leaked out is: