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Byju's Answer
Standard XII
Chemistry
Hydrate Isomerism
28 kg of N2 a...
Question
28 kg of N2 and 3 kg of H2 are mixed to produce NH3. The maximum amount of NH3 formed is.
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Q.
50.0
kg of
N
2
gas and
10.0
kg of
H
2
gas are mixed to produce
N
H
3
. The limiting reagent and amount of
N
H
3
formed are:
Q.
56
kg
of
N
2
(g)
and
10
kg
of
H
2
are mixed to produce
N
H
3
(g)
. Calculate the amount of
N
H
3
(g)
formed.
(assume the reaction goes to completion)
N
2
(
g
)
+
3
H
2
(
g
)
→
2
N
H
3
(
g
)
Q.
56 Kg of
N
2
gas and 10 Kg of
H
2
gas are mixed to produce
N
H
3
gas. Calculate the no of moles of ammonia gas formed.
Q.
50 kg of N2(g) and 10kg of
H
2
(
g
)
are mixed to produce
N
H
3
(
g
)
. Calculate the amount of
N
H
3
formed. Identify the limiting reagent in the production of the
N
H
3
.
Q.
Urea
(
N
H
2
C
O
N
H
2
)
is formed when
C
O
2
reacts with
N
H
3
.
C
O
2
+
2
N
H
3
⟶
N
H
2
C
O
N
H
2
+
H
2
O
N
H
3
and
C
O
2
are obtained in the following steps:
I
:
N
2
+
3
H
2
90
%
−
−
→
2
N
H
3
I
I
:
C
a
C
O
3
50
%
−
−
→
C
a
O
+
C
O
2
Amount of
N
2
and
C
a
C
O
3
required to produce
60
kg of urea are
X
kg and
Y
kg respectively. The value of
X
+
Y
(nearest integer value ) is
:
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