-29-26-7-3- -3 -5-3 -2-0

The correct option is B False .Given:[29 ( 2) {6 (7 3)}] ÷ [3 ×{5 + ( 3) × ( 2)}] ⇒ [29 ( 2) {6 4}] ÷ [3 ×{5 +6}] ⇒ [29 ( 2) {2}] ÷ [3 ×{11}] ⇒ ...

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Byju's Answer

Standard VII

Mathematics

Using Brackets

[29--26-7-3] ...

Question

$[29 - (- 2) {6 - (7 - 3)}] \div [3 \times {5 + (- 3) \times (- 2)}] = 0$

True

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False

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Solution

The correct option is B
False

.Given: $[29 - (- 2) {6 - (7 - 3)}] \div [3 \times {5 + (- 3) \times (- 2)}]$

$\Rightarrow$ $[29 - (- 2) {6 - 4}] \div [3 \times {5 + 6}]$

$\Rightarrow$ $[29 - (- 2) {2}] \div [3 \times {11}]$

$\Rightarrow$ $[29 + 4] \div [33]$

$\Rightarrow$ $33 \div 33$

$\Rightarrow$ $1$

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Similar questions

Q. Simplify:

[29 - (- 2) {6 - (7 - 3)}] \div [3 \times {5 + (- 3) \times (- 2)}]

Q. Simplify each of the following:

[29 - (- 2) \{6 - (7 - 3)\}] \div [3 \times {5 + (- 3) \times (- 2)}]

The lines = 2, = 5, y = 3 & y = –4 form a rectangle. Find equations of its diagonals.

Fill in the blank

\begin{matrix} 4 & 7 & (26) 7 & 3 & (29) 3 & 9 & (-) \end{matrix}

Evaluate each of the following: $(i) \frac{2}{3} - \frac{3}{5} (i i) \frac{- 4}{7} - \frac{2}{- 3} (i i i) \frac{4}{7} - \frac{- 5}{- 7} (i v) - 2 - \frac{5}{9} (v) \frac{- 3}{- 8} - \frac{- 2}{7} (v i) \frac{- 4}{13} - \frac{- 5}{26} (v i i) \frac{- 5}{14} - \frac{- 2}{7} (v i i i) \frac{13}{15} - \frac{12}{25} (i x) \frac{- 6}{13} - \frac{- 7}{13} (x) \frac{7}{24} - \frac{19}{36} (x i) \frac{5}{63} - \frac{- 8}{21}$

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[29−(−2){6−(7−3)}]÷[3×{5+(−3)×(−2)}] = 0

The correct option is B False .Given:[29−(−2){6−(7−3)}]÷[3×{5+(−3)×(−2)}] ⇒ [29−(−2){6−4}]÷[3×{5+6}] ⇒ [29−(−2){2}]÷[3×{11}] ⇒ [29+4]÷[33] ⇒ 33÷33 ⇒ 1

$[29 - (- 2) {6 - (7 - 3)}] \div [3 \times {5 + (- 3) \times (- 2)}] = 0$