29.5 mg of an organic compound containing nitrogen was digested according to Kjeldahr's method and the evolved ammonia was absorbed in 20 mL of 0.1 M HCl solution. The excess of the acid required 15 mL of 0.1 M NaOH solution for complete neutralization. Determine the percentage of nitrogen in the compound.

23.7

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25.4

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21.4

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29.5

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Solution

The correct option is A $23.7$
Moles of HCI reacting with ammonia = (moles of $H C I$ absorbed) - (moles of $N a O H$ solution required)

$= (20 \times 0.1 \times 10^{- 3}) - (15 \times 0.1 \times 10^{- 3})$

= moles of $N H_{3}$ evolved.

= moles of nitrogen in organic compound

$∴$ wt. of nitrogen in org. comp = $0.5 \times 10^{- 3} \times 14$
= $7 \times 10^{- 3} g$

% wt. = $\frac{7 \times 10^{- 3}}{29.5 \times 10^{- 3}} = 23.7$ %

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