The correct option is C a= 1/2 , 2 2a^2+5a+2=0 2a^2+4a+a+2=0 2a(a+2)+1(a+2)=0 (2a+1)(a+2)=0 a=( 1/2)>or>a=2 ...

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Conjugate of a Complex Number

2a2+ 5a +2

Question

$2 a^{2} + 5 a + 2$

a = \frac{- 1}{2}

0

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a = \frac{- 1}{2}

- 2

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a = \frac{1}{2}

0

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a = \frac{1}{2}

2

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Solution

The correct option is C $a = \frac{- 1}{2}$ , $- 2$
$2 a^{2} + 5 a + 2 = 0 2 a^{2} + 4 a + a + 2 = 0 2 a (a + 2) + 1 (a + 2) = 0 (2 a + 1) (a + 2) = 0 a = (\frac{- 1}{2}) o r a = 2$

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