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Question

(2a + b)3 - (a + 3b)3

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Solution

We have 2a+b3-a+3b3=2a+b-a+3b2a+b2+2a+ba+3b+a+3b2= a-2b4a2+b2+4ab+2a2+7ab+3b2+a2+9b2+6ab=a-2b4a2+2a2+a2+b2+3b2+9b2+4ab+7ab+6ab=a-2b7a2+13b2+17ab

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