Question

$2A+B\to C+D$
In this reaction, if we double the concentration of $A$, reaction rate become two times. And in another experiment, we double the concentration of $A$ and $B$, reaction rate again become two times. What is the order of this reaction?

• A. 1
• B. 3
• C. 2
• D. 1.5

Answer 1

The correct option is A 1

From the observation, we can see that changing $B$ has no effect on the rate and doubling the amount of the $A$ doubles the rate of the reaction.

Thus,

$Rate=k[A{]}^1$ satisfies the given data.

Thus order $=1$