2Ag - 3Bg - Cg - Dg - EgThe order of the given reaction is 72 and the experimental rate law of the given reaction is K -A-2-B-x-C-1- Find the value of -x-

For a given reaction: aA+bB+cC →Products If, Rate∝ [A]^p[B]^q[C]^r Overall order of the reaction is : (p+q+r) So, for 2A(g) nbsp; + 3B(g) + C(g) → D(g) + E(g ...

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Byju's Answer

Standard XII

Chemistry

Law of Mass Action

2Ag + 3Bg + C...

Question

$2 A (g) + 3 B (g) + C (g) \to D (g) + E (g)$
The order of the given reaction is $\frac{7}{2}$ and the experimental rate law of the given reaction is $K [A]^{2} [B]^{x} [C]^{1}$ . Find the value of 'x'.

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Solution

Order of a reaction:
For a given reaction:
$a A + b B + c C \to Products$
If,
$Rate \propto [A]^{p} [B]^{q} [C]^{r}$
Overall order of the reaction is :
$(p + q + r)$

So, for
$2 A (g) + 3 B (g) + C (g) \to D (g) + E (g)$

The experimental rate law is,
$R = K [A]^{2} [B]^{x} [C]^{1}$

Thus, the overall order of the reaction is
$(2 + x + 1)$

Order of given reaction is $\frac{7}{2}$
$∴$
$\Rightarrow 2 + x + 1 = \frac{7}{2}$
$x = \frac{7}{2} - 3$
$x = \frac{1}{2}$
Thr order of reaction with respect to B is $\frac{1}{2}$

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2A(g)+3B(g)+C(g)→D(g)+E(g) The order of the given reaction is 72 and the experimental rate law of the given reaction is K[A]2[B]x[C]1. Find the value of 'x'.

$2 A (g) + 3 B (g) + C (g) \to D (g) + E (g)$
The order of the given reaction is $\frac{7}{2}$ and the experimental rate law of the given reaction is $K [A]^{2} [B]^{x} [C]^{1}$ . Find the value of 'x'.